feat(mode_workflow): Part C 帖列表加「解构全部已采纳」按钮(复用 startExtract,按当前 tab 方向)

examples/mode_workflow/index.html

@@ -2196,6 +2196,7 @@
               >
                 批量解构
               </button>
+              <button class="btn sm" id="btn-extract-adopted" hidden>解构全部已采纳</button>
             </span>
           </div>
           <div
@@ -2924,8 +2925,20 @@
         const b = $("#btn-batch");
         b.disabled = !state.selected.size;
         b.textContent = state.selected.size ? `批量解构(${state.selected.size})` : "批量解构";
+        // 解构全部已采纳:有采纳帖才显示,带数量(口径同帖列表的 采纳 标记)
+        const adoptedN = (state.posts || []).filter((p) => p.adopted).length;
+        const ea = $("#btn-extract-adopted");
+        ea.hidden = !adoptedN;
+        ea.textContent = `解构全部已采纳(${adoptedN})`;
       }
       $("#btn-batch").onclick = () => state.selected.size && startExtract([...state.selected]);
+      $("#btn-extract-adopted").onclick = () => {
+        const cids = (state.posts || []).filter((p) => p.adopted).map((p) => p.case_id);
+        if (!cids.length) return toast("当前 query 下没有已采纳的帖子", "warn");
+        const dir = state.mode === "process" ? "工序" : "工具";
+        if (!confirm(`对该 query 下全部 ${cids.length} 个已采纳帖做${dir}解构?\n已解构过的会自动跳过/复用,不重复花钱。`)) return;
+        startExtract(cids);   // 复用:认领锁 + 解构去重 + showTask 轮询
+      };
 
       /* ════ 帖子详情弹层 ════ */
       /* 得分可能是字符串("1")或数字(10),统一解析;非数值返回 null */